Alan has two more than twice as many chocolates as does alice, and half as many chocolates as does nadia. if alice has βa' number of chocolates, then in terms of βa', how many chocolates do alan, alice and nadia have
Accepted Solution
A:
Alan has two more than twice as many chocolates as does alice Alan = 2Alice + 2 ----(1)
Alan has half as many chocolates as does nadia Alan = 1/2 Nadia so Nadia = 2Alan ----(2)
if Alice has 'a' number of chocolates from (1) Alan = 2a + 2 ----(3) from (2) and (3) Nadia = 2 (2a+2) = 4a+4 ----(4)
So Alan Alice and Nadia have (2a+2) + a + (4a+4) = 7a+ 6 #