MATH SOLVE

3 months ago

Q:
# Alan has two more than twice as many chocolates as does alice, and half as many chocolates as does nadia. if alice has βa' number of chocolates, then in terms of βa', how many chocolates do alan, alice and nadia have

Accepted Solution

A:

Alan has two more than twice as many chocolates as does alice

Alan = 2Alice + 2 ----(1)

Alan has half as many chocolates as does nadia

Alan = 1/2 Nadia

so Nadia = 2Alan ----(2)

if Alice has 'a' number of chocolates

from (1)

Alan = 2a + 2 ----(3)

from (2) and (3)

Nadia = 2 (2a+2) = 4a+4 ----(4)

So Alan Alice and Nadia have

(2a+2) + a + (4a+4) = 7a+ 6 #

Alan = 2Alice + 2 ----(1)

Alan has half as many chocolates as does nadia

Alan = 1/2 Nadia

so Nadia = 2Alan ----(2)

if Alice has 'a' number of chocolates

from (1)

Alan = 2a + 2 ----(3)

from (2) and (3)

Nadia = 2 (2a+2) = 4a+4 ----(4)

So Alan Alice and Nadia have

(2a+2) + a + (4a+4) = 7a+ 6 #