PLEASE ANSWER CORRECTLYPLEASE HURRYWILL GIVE BRAINLIEST An ellipse is represented using the equation . Where are the foci of the ellipse located? Check all that apply.(−29, 7)(19, 7)(−21, 7)(13, 7)(−5, −17)(−5, 31)EQUATION:

Answer:Options A and B.Step-by-step explanation:An ellipse is represented by the equation [tex]\frac{(x+5)^{2}}{625}+\frac{(y-7)^{2}}{49}=1[/tex]We have to find the foci of the given ellipse.Ellipse having equation [tex]\frac{(x-h)^{2}}{a^{2} }+ \frac{(y-k)^{2} }{b^{2} }=1[/tex]Then center of this ellipse is represented by (h, k) and foci as (c, 0) and (-c, 0).And c is represented by c² = a² - b²So we co relate this equation with our equation given in the question.a = √625 = 25b = √49 = 7and c² = (25)² - (7)²c² = 625 - 49 = 576c = ±√576c = ±24Now we know center of the ellipse is at (-5, 7) so foci can be obtained by adding and subtracting x = 24 from the coordinates of the center.Center 1 will be [(-5+24=19), 7] ≈ (19, 7)Center 2 will be [(-5-24=-29), 7] ≈ (-29, 7)Therefore, options A and B are correct.