MATH SOLVE

2 months ago

Q:
# what are the solutions to the quadratic equation x^2-16=0

Accepted Solution

A:

Simplifying this, we get:

(x+4)(x-4) = 0

Now, to get 0, we can replace x for one of these things to make 0, so:

x can either be 4, or -4

(x+4)(x-4) = 0

Now, to get 0, we can replace x for one of these things to make 0, so:

x can either be 4, or -4